1.Problem
http://poj.org/problem?id=3691
2.Idea
Here
3.Source
const int MAXK = 1000;
const int MAXLEN = 1010;
const string AGCT = "AGCT";
int nextState[MAXK][4];
bool ng[MAXK];
int dp[MAXLEN][MAXK];
int solve(const vector<string>& ngWords, const string& init) {
vector<string> pfx;
int n = ngWords.size();
// 状態の列挙
for (int i = 0; i < n; i++) {
string s = ngWords[i];
for (int j = 0; j <= (int)s.size(); j++) {
pfx.push_back(s.substr(0, j));
}
}
sort(pfx.begin(), pfx.end());
pfx.erase(unique(pfx.begin(), pfx.end()), pfx.end());
int K = pfx.size();
// 状態の遷移
for (int i = 0; i < K; i++) {
for (int j = 0; j < 4; j++) {
string s = pfx[i] + AGCT.substr(j, 1);
while (1) {
int nk = lower_bound(pfx.begin(), pfx.end(), s) - pfx.begin();
if (nk < K && pfx[nk] == s) {
nextState[i][j] = nk;
break;
}
s = s.substr(1);
}
}
}
// 状態がngかどうか
for (int i = 0; i < K; i++) {
ng[i] = false;
int sl = pfx[i].size();
for (int j = 0; j < n; j++) {
int wl = ngWords[j].size();
if (sl < wl) continue;
if (pfx[i].substr(sl - wl) == ngWords[j]) {
ng[i] = true;
break;
}
}
}
// dp
int length = init.size();
for (int i = 0; i <= length; i++) for (int k = 0; k < K; k++) {
dp[i][k] = INF;
}
dp[0][0] = 0;
for (int l = 0; l < length; l++) for (int k = 0; k < K; k++) {
if (dp[l][k] == INF) continue;
if (ng[k]) continue;
for (int j = 0; j < 4; j++) {
int plus = (init[l] == AGCT[j]) ? 0 : 1;
int ns = nextState[k][j];
if (ng[ns]) continue;
dp[l + 1][ns] = min(dp[l][k] + plus, dp[l + 1][ns]);
}
}
int ans = INF;
for (int k = 0; k < K; k++) {
if (ng[k]) continue;
ans = min(ans, dp[length][k]);
}
if (ans == INF) ans = -1;
return ans;
}
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
int T = 0;
int n;
while (cin >> n) {
if (n == 0) break;
T++;
vector<string> ngWords;
for (int i = 0; i < n; i++) {
string s;
cin >> s;
ngWords.push_back(s);
}
string init;
cin >> init;
printf("Case %d: %d\n", T, solve(ngWords, init));
}
return 0;
}
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