http://poj.org/problem?id=3041
2.Idea
Bipartite Matching
3.Source
#define MAX_V 1000
int V;
vector<int> G[MAX_V];
int match[MAX_V];
bool used[MAX_V];
void add_edge(int u, int v)
{
G[u].push_back(v);
G[v].push_back(u);
}
bool dfs(int v)
{
used[v] = true;
for (int i = 0; i < G[v].size(); i++) {
int u = G[v][i], w = match[u];
if (w < 0 || !used[w] && dfs(w)) {
match[v] = u;
match[u] = v;
return true;
}
}
return false;
}
int bipartite_matching()
{
int res = 0;
memset(match, -1, sizeof match);
for (int v = 0; v < V; v++) {
if (match[v] < 0) {
memset(used, 0, sizeof used);
if (dfs(v)) {
res++;
}
}
}
return res;
}
#define MAX_K 10000
int N, K;
int R[MAX_K], C[MAX_K];
void solve()
{
V = N * 2;
for (int i = 0; i < K; i++) {
add_edge(R[i] - 1, N + C[i] - 1);
}
printf("%d\n", bipartite_matching());
}
int main()
{
scanf("%d%d", &N, &K);
for (int i = 0; i < K; i++) {
scanf("%d%d", &R[i], &C[i]);
}
solve();
return 0;
}
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